30p^2+32p-14=0

Solution for 30p^2+32p-14=0 equation:

30p^2+32p-14=0

a = 30; b = 32; c = -14;
Δ = b2-4ac
Δ = 322-4·30·(-14)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-52}{2*30}=\frac{-84}{60}
=-1+2/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+52}{2*30}=\frac{20}{60}
=1/3
$